Integral of 1/(1 + tanθ)?

Question: How do I find ∫1/(1 + tanθ).dθ Thanks! Best Answers: Answer by germano∫ [1 /(1 + tanθ)] dθ = let tanθ = t θ = arctan t dθ = [1 /(t² + 1)] dt substituting, you have: ∫ [1 /(1 + tanθ)] dθ = ∫ [1 /(1 + t)] [1 /(t² + 1)] dt […] PR News Crimovies