Integrate: 1/(1-3x) + 1/(1+3x)?

Question: I have to prove it equals (1/6) ln[(1+3x)/(1-3x)] + c Any help would be appreciated Best Answers: Answer by clarissa∫(1/(1-3x) + 1/(1+3x)) dx = (-1/3)ln(1-3x) + (1/3)ln(1+3x) + c = ln(1+3x)/3 – ln(1-3x)/3 + c = ln[(1+3x)/(1-3x)]/3 + c uhhh. the coefficient isn’t 1/6 it’s actually 1/3, but that’s how you would do it. […] PR News Crimovies