Sn = [1/(1*2)] ……….?

Question: How to calculate the sum: Sn = [1/(1*2)] + [1/(2*3)] + [1/(3*4)] + … + {1/[n*(n+1)]} Best Answers: Answer by gudspelingUse partial fractions: 1/(n(n+1)) ≡ A/n + B/(n+1) A(n+1) + Bn ≡ 1 If n=0 A +0 = 1 A = 1 If n=-1 0 – B = 1 B = -1 1/(n(n+1)) = […] PR News Crimovies